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Old Aug 3, 2015 | 03:34 PM
  #1  
2Olds4U's Avatar
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Majored in rear tire demo
 
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From: Hingham, MA
What happened here?

As I was disassembling the front end, I noticed the left coil spring was distorted. I've never seen anything like this and didn't know if any of you had any ideas as to the cause.
Funny thing is that the car didn't really sit lopsided, but the left coil is at least 3 inches shorter than the right side.
Various theories encouraged!
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Old Aug 3, 2015 | 03:42 PM
  #2  
RROLDSX's Avatar
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Is your car's nickname Ilene?
Old Aug 3, 2015 | 04:02 PM
  #3  
oldcutlass's Avatar
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Collapsed or broken spring, rare but not uncommon. You need a new set.
Old Aug 3, 2015 | 04:06 PM
  #4  
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Kinda looks like the ole adjusting ride height with an acetylene torch trick
Old Aug 3, 2015 | 04:21 PM
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"Kinda looks like the ole adjusting ride height with an acetylene torch trick "

That was my guess. It's obvious two of the coils collapsed some how.
Old Aug 3, 2015 | 05:55 PM
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Octania's Avatar
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makes the spring stiffer
shorter, but stiffer.

why? Hmmm... mischief makers have reasons that confound the sane.
Old Aug 3, 2015 | 06:05 PM
  #7  
2Olds4U's Avatar
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Majored in rear tire demo
 
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From: Hingham, MA
Originally Posted by Octania
makes the spring stiffer
shorter, but stiffer.

why? Hmmm... mischief makers have reasons that confound the sane.
It did sit a bit lower than my other 67, but rode a lot softer for some reason.
I was never enthralled with the way it drove, but with an m21, super high (2.56) O rear, I suspect it was meant more for highway than strip.
Old Aug 3, 2015 | 08:32 PM
  #8  
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My drivers side spring in my 67 was broke in half when i got it. It still sat level.
Old Aug 3, 2015 | 10:24 PM
  #9  
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Considering that the springs are held captive and somewhat compressed at full rebound, and the car is rarely at full rebound, they may have sat equal when installed into the car. I think that one spring took a different set than the other over the years and that is what it ended up as. Observers will note that both springs have the same amount of coils and only one area is compressed. I would say that one spring is more compressed at rest than the other, but it isn't a shorter spring.

In case y'all care, spring force is F=-K(x) where H is Hooke's constant (and that varies per material and thickness of said spring) and X is how far you compress it. I would wager that the constant changed on the deformed one, but, once compressed into the car, probably didn't make that much of a difference overall, as part of the spring failed, but the rest of it uncompressed enough to balance it out.

A broken spring would work, I think, provided the ends didn't get past and inside each other.

Last edited by Koda; Aug 3, 2015 at 10:26 PM. Reason: Hooke's constant is K not H, duh.
Old Aug 4, 2015 | 07:02 AM
  #10  
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Originally Posted by RROLDSX
Is your car's nickname Ilene?
Used to date a girl named Ilean, left her cause she always took forever having one leg and all.
Old Aug 4, 2015 | 02:22 PM
  #11  
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Originally Posted by Koda
spring force is F=-K(x) where H is Hooke's constant
I think you have a K where you wanted to put an H.
Old Aug 4, 2015 | 06:13 PM
  #12  
2Olds4U's Avatar
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Majored in rear tire demo
 
Joined: Oct 2012
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From: Hingham, MA
Originally Posted by Fun71
I think you have a K where you wanted to put an H.
No, he's right. It's F=ck(T).
Old Aug 7, 2015 | 06:23 PM
  #13  
2Olds4U's Avatar
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Majored in rear tire demo
 
Joined: Oct 2012
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From: Hingham, MA
Originally Posted by rjohnson442
Used to date a girl named Ilean, left her cause she always took forever having one leg and all.
Was her last name Dover?
Old Aug 7, 2015 | 07:08 PM
  #14  
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I think she had a brother Ben...
Old Aug 7, 2015 | 08:44 PM
  #15  
Koda's Avatar
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Originally Posted by Fun71
I think you have a K where you wanted to put an H.
I forgot to edit the second H to K. Spring force is some constant times the compression distance.
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